Basic unix script to count files of various permissions

[dannytimpone]

I have a project due in a few hours to count how many files and subdirectories are in a directory and to count the number of readable, writable, and executable items. I have this code so far, but my counters always return zero. Please help me.

#!/bin/bash

r=0
w=0
x=0
f=0
d=0

if [ "$1" = "" ] ; then
 echo "Usage: homework4.sh <direcotry_name>"
elif [ ! -d  "$1" ] ; then
 echo "$1 : no such directory"
else
 for files in `ls -1  ~/$1`
  do
    [ -r "${files}" ] && r=`expr $r + 1` #experimenting with diff technique here

    if [ -x $files ] ; then
    $x = `expr $x + 1`
    fi

    if [ -w $files ] ; then
     w = `expr $w + 1`
    fi

    if [ -d $files ] ; then
     d = `expr $d + 1`
    fi

    if [ -f $files ] ; then
     f = `expr $f + 1`
     fi

 done

echo "Number of files : $f "
echo "Number of directories : $d "
echo "Number of readable items : $r "
echo "Number of executable items : $x "
echo "Number of writeable items : $w "
fi
exit

[kbw]

I would use ls -AlR to get the files with attributes. You can use grep or egrep to parse the output for flags and wc -l to count the number of lines in the output.

And there's the option of running multiple times for each case or storing the full list in a temp file.

Good luck.