Help Fixing Program

[yqGNwA7f]

Ok, basically I am making a console arithmetic calculator just for learning, I am new. I can't seem to figure out why no matter what method I use, it adds it even if I chose to multiply, please look at the code and tell me how to fix it, or help me in any way you can, all help is appreciated. Thanks in advance.

#include "stdafx.h"
#include <iostream>
#include "conio.h"
#include <cstdlib>
#include <cstdio>
// using namespace std;

int num1;			// first int
int num2;			// second int

int method;			// method e.g. [+, -, *, /]

int add;			// addition [+]
int sub;			// subtraction [-]
int mul;			// multiplication [*]
int divide;			// dividesion [/]
int mod;			// modulous [%]

/*
int quo;			// answer to division [/]
int sum;			// answer to addition [+]
int difference;		// answer to subtraction [-]
int product;		// answer to multiplication[*]
*/

int _tmain(int argc, _TCHAR* argv[])
{
	std::cout << "Enter first integer or float value: " << std::endl;
	std::cin >> num1;

	std::cout << "Enter second integer or float value: " << std::endl;
	std::cin >> num2;

	std::cout << "Enter method: add, sub, mul, divide, mod" << std::endl;
	std::cin >> method;

	if( method == add )
	{
		std::cout << "The answer is: " << num1 + num2 << std::endl;
	}
	else if( method != add && method == sub )
	{
		std::cout << "The answer is: " << num1 - num2 << std::endl;
	}
	else if( method != add || sub && method == mul )
	{
		std::cout << "The answer is: " << num1 * num2 << std::endl;
	}
	else if( method != add || sub || mul && method == divide )
	{
		std::cout << "The answer is: " << num1 / num2 << std::endl;
	}
	else if( method != add || sub || mul || divide && method == mod )
	{
		std::cout << "The answer is: " << num1 % num2 << std::endl;
	}
	else
	{
		std::cout << "Unknown function, please use [ +, -, *, / ]" << std::endl;
	}
	
	system("PAUSE");
}

[Muckle ewe]

Few problems here. First of all...

It's your usage of ||. I believe (could be wrong here mind) that you have to be explicit each time you use || so you would have to do method != add || method != sub, etc...

But you don't need the != part either.

Just use

else if(method == sub ) instead (for example)


BUT!

I'd like you to tell me what sub,add, etc actually are? They haven't been set to anything so the statement if (method == add) for example doesn't actually mean anything.
You could assign add,sub, etc values such as 1,2,3 and use
if (method == 1) for example.

Or you could use strings and have

string method;

std::cout << "Enter method: add, sub, mul, divide, mod" << std::endl;
getline(std::cin, method);


if (method == "add")
{
// do some addition.
}

[yqGNwA7f]

Originally I had it as else if(method == sub ) but I thought maybe it'd fix the program, I don't really understand alot of C++. Just basic math, but how do I make it so when I enter a method when it asks for (e.g. add, sub, mul, divide, mod) that it returns the two numbers either added, multiplied etc depending on what method was entered by the user?

[Muckle ewe]

set values of add, sub, etc...

So have,

int add = 1;
int sub = 2;
int mul = 3;
int divide = 4;
int mod = 5;

Then in your loop put, for example...

if( method == 1 )
{
// do some addition.
}
else if (method == 2)
{
// do some subtraction
}

[yqGNwA7f]

#include "stdafx.h"
#include <iostream>
#include "conio.h"
#include <cstdlib>
#include <cstdio>

int num1;			// first int
int num2;			// second int

int method;			// method e.g. [+, -, *, /]

int add = 1;		// addition
int sub = 2;		// subtraction
int mul = 3;		// multiplication
int divide = 4;		// division
int mod = 5;		// modulous

/*
int quo;			// answer to division [/]
int sum;			// answer to addition [+]
int diff;		// answer to subtraction [-]
int prdct;		// answer to multiplication[*]
*/

int _tmain(int argc, _TCHAR* argv[])
{
	std::cout << "Enter first integer: " << std::endl;
	std::cin >> num1;

	std::cout << "Enter second integer: " << std::endl;
	std::cin >> num2;

	std::cout << "Enter method: add (1), sub (2), mul (3), divide (4), mod (5)" << std::endl;
	std::cin >> method;

	if( method == 1 )
	{
		std::cout << "The answer is: " << num1 + num2 << std::endl;
	}
	else if( method == 2 )
	{
		std::cout << "The answer is: " << num1 - num2 << std::endl;
	}
	else if( method == 3 )
	{
		std::cout << "The answer is: " << num1 * num2 << std::endl;
	}
	else if( method == 4 )
	{
		std::cout << "The answer is: " << num1 / num2 << std::endl;
	}
	else if( method == 5 )
	{
		std::cout << "The answer is: " << num1 % num2 << std::endl;
	}
	else
	{
		std::cout << "Unknown function, please use [ +, -, *, / ]" << std::endl;
	}
	
	system("PAUSE");
}

This code works, thank you so much for your help!