c++

[4y79216C]

hello everyone can someone help me about array plsss i really need help right now

using one-dimensional array. create a program that will count the number of the same intries in a series number based on the user specific no. to count
EXPECTED output
Enter no.1:2
Enter no.2:1
Enter no.3:1
Enter no4:2
what number to v=count?1
total number 1 is 2

should use a counter
i appretiate those who will answer

this is my code
#include<iostream>
using namespace std;
int main()
{
int n,hn,nc;
int i;
int count;
float totaln;
count=0;

cout<<"ENTER MANY NUMBERS TO INPUT?:"<<endl;
cin>>hn;

for(i=1;i<=hn;i++)
{

cout<<"ENTER NUMBER :"<<i<<":";
cin>>n;}



cout<<"WHAT NUMBER TO COUNT:"<<endl;
cin>>nc ;
count=0;
totaln+=n;

cout<<"THE TOTAL NUMBER IS:"<<totaln;


system("PAUSE");
}

[Kazekan]

First off, please put your code in code <> brackets. The button for this can be found under the Format box to the right of the text window when creating/editing a thread.

Secondly, you haven't even attempted to implement your array. :( As it stands, your user will enter in "n", "hn" times in a row, but "n" will just be overwritten each time. It is stored nowhere. Also, variables such as "i" that are to be used within a for loop can be completely defined within the for loop itself, unless you need to reference the last value of "i" later on or something. Therefore, your for loop becomes:

for(int i=1;i<=hn;i++)
{

}

Within your first for loop you should be using "i" to also place the values within your array (which you haven't declared yet). Technically you'll be using i-1, since you'll want to start at 0, and not 1, since someArray[0] will coincide with the first spot in the array.

[sheraz07]

susied this is not codding for arrays u should declare first array.......like A[10];..........etc then u use for loop for it
learn tutorial of arrays......
int a[5];
int count=0;
int sum=0;
for(int i=1;i<=5;i++)
{
cout<<"enter number";
cin>>a[i];
sum=sum+a[i];
count++;
}
cout<<count<<endl;
cout<<"array sum="<<a[i];

[4y79216C]

yayks,,, like this

#include<iostream>
using namespace std;
int main()
{

string name[50]={};
int s[]={};
int i;
int hn;
int l;
int k;
int n;
int largest;
int smallest;

float average;
cout<<"ENTER MANY many students?:"<<endl;
cin>>hn;
for(i=1;i<hn;i++)
{
cout<<"ENTER name of students :"<<i<<":" ;
cin>>n;{
cout<<"ENTER SCORE:";
cin>>l;}

for(i=0;i<hn;i++){
if(s[i]>largest)
largest=s[i];

for(i=0;i<hn-1;i++){
if(s[i]<smallest)
smallest=s[i];}

}}

cout<<"THE HIGHEST IS"<<s[i];



system("PAUSE");
}

i don't know how to calculate

[DEBASISH DAS]

string name[50]={};

[S G H]

Code tags please. Also arrays are fixed-size. use std::vector instead.

[4y79216C]

here's my new code right now
#include<iostream>
using namespace std;
int main()
{

int a[]={};
int count=0;
int sum=0;
int i,hn,w;

cout<<"ENTER MANY NUMBERS TO INPUT?:"<<endl;
cin>>hn;
for(i=1;i<hn;i++)
cout<<"ENTER NUMBER :#"<<i-1;
cin>>a[i];
cout<<"WHAT NUMBER TO CUONT:"<<endl;
cin>>w;
{
sum=sum+a[i];
count++;
}
cout<<count<<endl;
cout<<"TOTAL:"<<a[i];
system("PAUSE");


}

but i think closer

[S G H]

EssGeEich wrote:

Code tags please. Also arrays are fixed-size. use std::vector instead.

Follow, Please.

http://www.cplusplus.com/articles/z13hAqkS/
http://www.cplusplus.com/reference/vector/vector/

[4y79216C]

#include<iostream>
using namespace std;
int main()
{

int a[]={};
int count=0;
int sum=0;
int i,hn,w;

cout<<"ENTER MANY NUMBERS TO INPUT?:"<<endl;
cin>>hn;

for(i=1;i<hn;i++){

cout<<"ENTER NUMBER :#"<<i-1;
cin>>a[i];

cout<<"WHAT NUMBER TO CUONT:"<<endl;
cin>>w;
{
sum=sum+a[i];
count++;
}
cout<<count<<endl;
cout<<"TOTAL:"<<a[i];
system("PAUSE");


}

[modoran]

That program does not need any array or std::vector, it works without it.

How, it is left as an exercise for the OP.

[4y79216C]

but its say using one dimensional

[S G H]

modoran, read it again and try to translate the phrase "Enter many numbers to input?". There is a way not-to-use std::vector I know, but I won't say which one because...

modoran wrote:

...it is left as an exercise for the OP.

[modoran]

I was thinking of something like this:

#include <iostream>

using namespace std;

int main()
{
    int Count = 0;
    int Numbers = 0;
    int Num = 0;

    cout << "Enter many numbers to input ?" << endl;
    cin >> Numbers;

    for (int i = 0; i < Numbers; i++) {
        cout << "Enter #" << (i+1) << endl;
        cin >> Num;
        Count += Num;
    }

    cout << "The sum of total " << Numbers << " is " << Count << endl;
    return 0;
}

[4y79216C]

ok thanks for the codes.. i change in the last part

#include <iostream>

using namespace std;

int main()
{
    int Count = 0;
    int Numbers = 0;
    int Num = 0;
   int w;
    cout << "Enter many numbers to input ?" << endl;
    cin >> Numbers;

    for (int i = 0; i<Numbers; i++) {
        cout << "Enter #" << (i+1) << endl;
        cin >> Num;}
        
    cout<<"WHAT NUMBER TO CUONT:"<<endl;
    cin>>w;
    Count += Num;
    

    cout << "The sum of total " << w << " is " << Count << endl;
    system("PAUSE");

}

but it doesn't work :(
when i enter

Enter many numbers to input ? :2
Enter #1:2
Enter #:2 3
WHAT NUMBER TO CUONT: 5

total number 5 is 6

instead of like this
total number 5 is 0
beacuse i 5 has not belong to what i enter

[modoran]

Sorry, I misunderstood your question. If you want to count a occurence of a number, the code could be this:

#include <iostream>

using namespace std;

int main()
{
    int Count = 0;
    int Numbers = 0;
    int Num = 0;
    int Search = 0;

    cout << "How many numbers do you want to enter ?" << endl;
    cin >> Numbers;

    cout << "What number occurence to search for ?" << endl;
    cin >> Search;

    for (int i = 0; i < Numbers; i++) {
        cout << "Enter #" << (i+1) << endl;
        cin >> Num;
        if (Num == Search)
            Count++;
    }

    cout << "Total occurences of number '" << Search << "' is " << Count << endl;
    return 0;
}

[4y79216C]

ahhh .. sorry for disturb but its always answer 0. Im trying to understand this but i dont how to be like this(correct answer)
how many want you to enter?: 4
enter #1: 2
enter #2: 2
enter #3: 2
enter #4: 2
What number to be count?: 2
the total number of 2 is "4"
hmmmm

[S G H]

It seems all right to my eyes. Copy-pasted the code and did what you wrote, worked a charm.

[4y79216C]

near to finish
but my problem is the number i will enter will be add instead of searching how many numbers??

[Imadatobanisa]

Be more detailed - and specific.

[4y79216C]

Thanks for everything and for codes it helps me a lot thank for all your concerned