So, i wrote this code:

 ``123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051`` `````` //On a certain day the British pound was equivalent to \$1.487 U.S., the French franc was //\$0.172, the German deutschemark was \$0.584, and the Japanese yen was \$0.00955. //Write a program that allows the user to enter an amount in dollars, and then displays this //value converted to these four other monetary units. #include #include using namespace std; int main() { float pound = 1.478; float franc = 0.172; float deutschemark = 0.584; float yen = 0.00955; int dollar; int menu; pound = dollar/pound; franc = dollar/franc; deutschemark = dollar/deutschemark; yen = dollar/yen; cout << "Money Changer:" << endl << endl; cout << "1. Input ammount (\$)" << endl << "2. Exit" << endl << "How can I help you: "; cin >> menu; cout << endl; if(menu==1) { cout << "Insert the ammount: "; cin >> dollar; cout << endl; cout << "The money you converted: " << endl; cout << "Pound= " << setprecision(2) << pound << endl << "Franc= " << setprecision(2) << franc << endl <<"Deutschemark= " << setprecision(2) << deutschemark << endl << "Yen= " << setprecision(2) << yen << endl; } else if(menu==2) { cout << "Thanks for using our service." << endl; } else { cout << "Please select the menu number provided." << endl; } return 0; } ``````

and the output:

 ```Money Changer: 1. Input ammount (\$) 2. Exit How can I help you: 1 Insert the ammount: 10000 The money you converted: Pound= 1.6e+006 Franc= 1.4e+007 Deutschemark= 4e+006 Yen= 2.5e+008 Process returned 0 (0x0) execution time : 3.539 s Press any key to continue. ```

My question is:

1. How to display the decimal without the 'e'?
2. And also, how to display only the last 2 digits after the comma?

Thanks,
God bless you
that shouldn't be your main concern.

You have not initialised dollar, which is why your maths is cack.
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Any other else want to help me?
Or do you seriously think 10 thousand dollars is the equivalent of 1.6 million english pounds?
I would make these values into constants:
 ``1234`` `````` const float pound = 1.478; const float franc = 0.172; const float deutschemark = 0.584; const float yen = 0.00955;``````

Don't attempt to assign any other value, for example don't do this: `pound = dollar/pound;`
Instead, define new variables for any subsequent calculations.
For a single calculation it would not matter very much, but if the user needed to enter a series of different dollar amounts, you'd want the original conversion rates to remain unaltered.

As well as that, you can't carry out the actual conversion until after line 32:
`cin >> dollar;`
That is, until the user has entered the value for dollar, it isn't possible to convert that amount into any other currency.

as for the original question, try
`cout << fixed << setprecision(2);`
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he's doing the calculations before he's asked the user for input :s
Oh my god mutexe was right.. Im sorry, im really sorry, hahahaha thx mutexe
Wait a minute, question number two still a problem. So i change the code like this:

 ``123456`` ``````cout << "The money you converted: " << endl; cout << "Pound= " << p << setprecision(2); cout << endl << "Franc= " << f << setprecision(2); cout << endl <<"Deutschemark= " << d << setprecision(2); cout << endl << "Yen= " << y << setprecision(2); cout << endl;``````

and still not showing only the last 2 digits :S
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You missed part of my previous comment:
`cout << fixed;`
Also, this must go before the actual values you wish to output, not afterwards.
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Thanks Chervil, God bless you :)
BTW...

All standard i/o manipulators which set or reset something, with the exception of setw, are "sticky" (i.e. do not reset after use); so the above could also be written as (with fixed added):

 ``1234567`` ``````cout << "The money you converted: " << endl; cout << setprecision(2) << fixed; cout << "Pound= " << p; cout << endl << "Franc= " << f; cout << endl <<"Deutschemark= " << d; cout << endl << "Yen= " << y; cout << endl;``````

or even as a single cout statement, as you had originally.

 ``12345678`` ``````cout << "The money you converted: " << endl << setprecision(2) << fixed << "Pound= " << p << endl << "Franc= " << f << endl << "Deutschemark= " << endl << "Yen= " << y << endl << endl; // endls look better at the ends of lines to me... ``````

Andy

PS
- the i/o manipulators that don't set/reset anything those which do something: endl, ends, flush and the new C++ manips: get_money, put_money, get_time, put_time.
- the sticky manipulators are all setting a flag
- setw behave the way is does as that's what ios_base method it calls (width) does itself.

 ``12345`` `````` cout << "set width to 8\n\""; cout.width(8); cout << f; size_t w = cout.width(); cout << "\"\n\"width = " << w << "\"" << endl;``````

 ```set width to 8 " 2.3" "width = 0"```

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