need help! how to create a simple password program using if statement

[enri357]

so i need a simple program for password identifier so please help...
:)

#include <iostream>
using namespace std;

int main()
{
	char Password=PLP;
	
	cout<<"please enter password \n";
	cin>>Password;
	if(Password == PLP)
		cout<<"Password Accepted \n";
	else
		cout<<"Invalid Password \n";

	return 0;
}

[nvrmnd]

Ok, first lets learn some basics:

If you want a variable that will hold more than one char ( which is called "string" or "array of char" you have to declare it like this:

char Password[] // this is also called "array" of char, You will learn this someday...;

and since you want a variable that will hold the input of the user, you do not need to assign any value to it... you should just declare it like this:

char Password[];

and in line 10 when comparing string values( which is a char greater than 1 ) you should enclosed PLP in quotes since this is a string and strings are always enclosed in quotes:

if( Password == "PLP" ) { ... }

And, if you want you can also declare using: string Password;.
But, you should first #include <string> to make that work..
That is just the same as declaring char Password[];


Hope you understand it!!!

[MrTrollFace]

Many mistakes, did you started c++ or just jumped to this program. Whatever, here is the corrected form:

#include <iostream>
using namespace std;

int main()
{
	char Password [];
	
	cout << "please enter password \n";
	cin >> Password;
	if(Password == "PLP")
        {// I prefer to use these
		cout << "Password Accepted \n";
	}
        else
	{
		cout << "Invalid Password \n";
	}
	return 0;
}

You can also use string but you must include it; #include<string> and then no need of [code][][code]

[vlad from moscow]

#include <iostream>
#include <string>

using namespace std;

int main()
{
	const char SecretWord[] = "PLP";
	string Password;
	
	cout << "please enter password: ";
	cin>>Password;

	if ( Password == SecretWord )
		cout << "Password Accepted \n";
	else
		cout << "Invalid Password \n";

	return 0;
}

[vlad from moscow]

@MrTrollFace

Many mistakes, did you started c++ or just jumped to this program. Whatever, here is the corrected form:

 #include <iostream>
using namespace std;

int main()
{
	char Password [];
	
	cout << "please enter password \n";
	cin >> Password;
	if(Password == "PLP")
        {// I prefer to use these
		cout << "Password Accepted \n";
	}
        else
	{
		cout << "Invalid Password \n";
	}
	return 0;
}

May I repeat your words?:)

Many mistakes, did you started c++ or just jumped to this program.

[MrTrollFace]

@vlad from moscow
Why do you make a const char? Why? Why do you make your work harder?

[coder777]

Why do you make a const char? Why? Why do you make your work harder?

why is this harder? const prevents from accidentally overwriting data and it improves optimization by the compiler

[vlad from moscow]

@MrTrollFace

Why do you make a const char? Why? Why do you make your work harder?

it is harder only in your head because you do not know C++.:)

[enri357]

thanks for the help guys! since you guys know things around here could any of you help me with a adding loop prog???
:D