How to write (rand)

[enemy]

Please is theere a way to write this shorter?

  int a=rand();
int b=rand();
int c=rand();

Many thanks!

[Albatross]

You can improve it a bit by doing this:
int a = rand(), b = rand(), c = rand();

-Albatross

[Disch]

If you're talking about having multiple variables that are similar... then naming them with incremental names (like 'a', 'b', 'c') is almost always a bad idea.

You're usually better off using an array:

int values[3];

for( auto& x : values )
    x = rand();

// or... if you're still living in the past and can't use basic C++11 features yet...
//   this for loop is equivalent:
for( int i = 0; i < 3; ++i )
    values[i] = rand();

While this isn't "shorter", it scales up much better. So if you need to change it so you have 20 variable instead of just 3... all you have to do is make the array bigger. Whereas if they all had unique names, you'd have to copy/paste a bunch of code.

[enemy]

Hello!
I have to get more random numbers, but with each I have to do different operations.

Is there any way to "generate" more automatically different names for each of the random number?


Can I write: for (int i=int a; i<=z; a++) ???

Or shoul dit be somehow connected with "char" ?

Many thanks!

[JLBorges]

#include <iostream>
#include <cstdlib>
#include <ctime>
#include <vector>
#include <algorithm>

int main()
{
    std::srand( std::time(nullptr) ) ; // seed the C lcg

    unsigned int z ;
    std::cout << "how many random numbers? " ;
    std::cin >> z ;

    std::vector<int> numbers(z) ; // vector of z numbers

    // fill it up with 'z' random numbers
    std::generate_n( numbers.begin(), z, std::rand ) ;

    // or: fill it up with 'z' random numbers
    for( int& v : numbers ) v = std::rand() ;
}