Finding 2 Kings in the Chess Game

[Chicken]

Hi, I am currently working on a chess game, and I am almost done, but all I need to do at the moment is to check my board to see if there are two kings left on the board, so if there is only 1 king left on the board the game is over. I currently have this:

bool Board::stillTwoKings () const
{
for (int col = 0; col < BOARD_HEIGHT; col++)
{
for (int row = 0; row < BOARD_WIDTH; row++)
{
if(board[col][row] == 'K' && board[col][row] == 'k')
cout << "YOUR GAME HAS ENDED" << endl;
}
}
return true;

But it is not working.. I keep trying different things, and I don't know how to cast the thing right... I was wondering if anyone could lead me to the right way? Thank you :)

[firedraco]

Your && is incorrect, assuming board is a 2d array of chars, then it can't possibly be 'k' *and* 'K' at the same time.

[helios]

Kings are never captured. The game ends when the king can't move in any direction without entering check.

[Chicken]

helios: Well in my case we don't have to check if it is in check we have to capture the king for the game to end.. so I don't know what to do..

firedraco: would it make a difference if I used ||?

[jsmith]

The easiest way is to count the number of kings on the board. After the loops, if the count is less than 2, then
the game is over. A square has a king iff the square is 'K' OR the square is 'k'.

[chrisname]

As Helios said, the King doesn't get taken anyway. Checkmate occurs by one player surrounding the enemy King such that he can't, again as Helios said, move without entering check.

[Disch]

cannot move without entering check = stalemate (tie)
cannot move without ESCAPING check = checkmate (lose)