Return array from functions ?

[YosofShihsbi]

Hi , everyone !
how to return an array from a function ?
just like this code ?

#include<iostream>
using namespace std;
int factors(int x)
{
	int arr[1000];
	for(int i=1;i<=x;i++)
	{
		if(x%i==0)
			arr[i]=x/i;
	}
	return arr;
}
int main()
{
	int x=60;
	factors(x);
}

[AbstractionAnon]

Return a pointer to the base of the array.

just like this code ?

What code?

[YosofShihsbi]

It's there :)

[YosofShihsbi]

int* pointer;
pointer=arr; 

like that ?

[AbstractionAnon]

No.

Line 5: arr is a local variable. It goes out of scope when factors() exits, therefore the memory occuped by arr is no longer valid.

Line 4: You're declaring that factors() returns an int, not a pointer.

Line 16: Even if the memory returned by factors() was valid, you're ignoring the pointer returned by factors().

You have a couple of options:
1) Pass the array as an argument when calling factors().
2) Allocate the array dynamically.