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Limit Login Attempt without return 0!

tunadinc (2)
Hello everyone, i am totally new to C++. I use DevC++ for my project but i am stuck in one case. I found a lot of examples to limit login attempt. Here i write it into a int main function but i want code to stop after 3 falied attempts, and i want code to keep running, not return to zero in case of succesfull login, please anyone help?

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  int main(){
	
	
system("cls"); ///clear the console window


string username;
string password;
int attempts = 0;


for (int attempts = 0; attempts < 3; attempts++ )
{
    cout << "Enter your username: " << endl;
    cin >> username;
    cout << "Enter your password: " << endl;
    cin >> password;

    if ( username == "billy" && password == "bob" )
    {
      	cout << "Access granted" << "\n" <<endl;
	
break;
    }

    else
    {
    cout << "Incorrect username/password combination. Please try again." << "\n" <<endl;
    
	}

    cout << "Maximum attempts reached." << endl;  
}

 return 0;




    FILE *fp, *ft; /// file pointers
    char another, choice;
 
    /** structure that represent a employee */
    
    struct emp{
        char name[40]; ///name of employee
        char gender[40];
        char email[40];
        
        int studentnumber;
        int phonenumber;
		int age; /// age of employee
		
		char course[40];
        int grade;
	};
.
.
.

The last part is just a little part of program.
Last edited on
AbstractionAnon (6954)
Your return 0 is in the wrong place.

Move line 35 to after line 32.
vxk (147)
most new compilers don't even need return 0; statement these days .Clang is one of them .
AbstractionAnon (6954)
That doesn't change the fact the OP has the return in wrong location.
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