Help with assignment

[mee95]

Hi! If someone has time, could you look over this assignment that i have for school?

It shouldnt be long but i dont know how to write the code so if someone could hint what i should do it would be great.

Ok so the text is:

Specify the natural number n for which it is worth that the n^2 - 3 is divisible by the square of the number larger than 1.

So basically you need to enter a number from the keyboard and the program should tell me back if the problem above is true for that number or not.

Would be greatly appreciated if someone helped out.

[48T7M4Gy]

Try some pseudocode:

1. input a number
2. square the number and subtract 23 from it
3. store this as the reference number
3. for all numbers (integers) greater than 1 test whether it will divide evenly into the reference
4. if it does then display the number
5. continue looping up to square root of the reference.

[mee95]

Hmmm ok so i did something... but its not working well...
mainly when i want to enter the number n or m its not working properly as in it accepts numbers which are over 1000
it fixes itself if i turn the signs to the other side but my professor said that i should do it this way. Im not sure where excately the mistake is.

#include <iostream>
#include <cmath>

using namespace std;
int i, j, k, q, m;
double s;

int main () {
do{
    cout<<"Enter number n [1-1000]:"<<endl;
    cin>>i;}
while((i>=1) && (i<=1000));

j=(pow(i,2)-2);

cout<<"n^2-3 is:"<<j<<endl;

do{
cout<<"Enter number m, which will be squared and then used as a divisor [2-1000]:"<<endl;
cin>>m;}
while ((m>=2) && (m<=1000));

q=pow(m,2);

s=j/q;

if (s==int()) {
    cout<<"Number "<<j<<" is divisible with the squared number "<<m<<endl;}
else{
    cout<<"Number "<<j<<" is not divisible with the squared number "<<m<<endl;}

return 0;
}

[MikeyBoy]

Your do...while loop from lines 9 - 12 doesn't look right. It will continually loop for as long as the condition (i>=1) && (i<=1000) is true. In other words, it will keep asking the user to input a value, until the user enters a value that's outside the range 1 - 1000, at which point it will proceed to use that value.

[mee95]

Solved it, thank you :)

[MikeyBoy]

You're welcome! Glad it worked out :)