Are iterators just pointers wrapped around some classes?

[zan nabil]

The output is same .....

  
string p = "Hola";
printf("%d\n",p.begin());

char *k;
k = &p[0] ;

printf("%d",k);

Then can i assume iterators are just fancy pointers ? And , I can't cout iterators even though i can cout pointers ?

cout<<k<<nln; //valid
cout<<(int)k<<nln; //valid
cout<<s.begin()<<nln; //not valid 

[coder777]

Then can i assume iterators are just fancy pointers ?

No. Do not make guesses about hidden implementation details.

[Duthomhas]

Iterators are designed to look and behave like pointers.

Chances are, though, that they are a class object and not a simple pointer.