Initializing a hash table structure in a class

[C0UG3R]

So I have an assignment where I have to make a hash table and I can't seem to get past the first part of allocating space for it and setting all the addresses equal to NULL.

Here is my header file:

    #ifndef _CONGERA6H_H
    #define _CONGERA6H_H

    const int MAX_STRING = 80;
    typedef char Element300[MAX_STRING + 1];

    class HT300
    {
    public:
        HT300(const int);
        ~HT300();
        void search300(const Element300);
        void view300() const;
    private:
        const int MAX_TABLE;
        struct HTNode300
        {
            Element300 reserved;
            int hashed, probed, matched;
        };
        HTNode300 * theTable;
        HT300();
        HT300(const HT300 &);
        int hash300(const Element300) const;
        void create300();
        void fill300();
    };

    #endif 

And here is the functions in my implementation file that are relevant to the question.

    #include <iostream>
    #include <cstring>
    #include <fstream>
    #include "congera6h.h"
    using namespace std;

    HT300::HT300(const int size) : MAX_TABLE(size)
    {
        theTable = new HTNode300[size];
        create300();
    }

    void HT300::create300()
    {
        While (theTable
        strcpy(aTable, '\0');

    }

I'm not sure if I'm even setting the table up correctly in the constructor. I know for a fact that we have to use a new operator in the constructor and then initialize all the addresses to NULL in the create300 function.

[coder777]

I'm not sure if I'm even setting the table up correctly in the constructor.

It's correct.

To initialize theTable use another constructor:

        struct HTNode300
        {
            Element300 reserved;
            int hashed, probed, matched;

            HTNode300() : hashed(0), probed(0), matched(0)
            {
              reserved[0] = 0;
            }
        };

With this you don't need create300().