Print 5 numbers per line

[cuttinace]

This program checks if a number is prime and if it isn't prime outputs the divisors

Lines 33-48 outputs the divisors and I want them to come out 5 per line.

#include <iostream>
#include <iomanip>
#include <string>
using namespace std;

int main()
{
	int num, count = 0, divisor;
	string choice;
	cout << "This program will determine if a number between 1 and 1000 is prime" << endl;
	do
	{
		cout << "Please enter a number ";
		cin >> num;
		while (num < 1 || num > 1000)
		{
			cout << "Enter valid number ";
			cin.clear();
			cin.ignore(200, '\n');
			cin >> num;
		}
		for (divisor = 1; divisor <= num; divisor++)
		{
			if (num % divisor == 0)
				count++;
		}
		if (count == 2)
		{
			cout << num << " is prime" << endl;
		}
		else
			cout << num << " is not prime" << endl;
		while (count > 2)
		{
			cout << "Divisors: ";
			divisor = 1;
			while (divisor <= num)
			{
				if (num % divisor == 0)
				{
					cout << divisor << "\t";
				}
				divisor++;
			}
			count -= 16;
			cout << "\n";

		}
		cout << "\n";
		cout << "Would you like to check another number? (y or n) ";
		cin >> choice;
		while (choice != "y" && choice != "Y" && choice != "n" && choice != "N")
		{
			cout << "Please enter y for yes or n for no ";
			cin.clear();
			cin.ignore(200, '\n');
			cin >> choice;
		}
		if (choice == "n" || choice == "N")
			return (0);
	} while (choice == "y" || choice == "Y");
}

[jonnin]

int ctrl = 1;

...
cout << divisor etc...

if(ctrl%5 == 0)
cout << endl;
ctrl ++;

[cuttinace]

Thanks jonnin, I ended up formatting it like this and it works.

while (count > 2)
		{
			cout << "Divisors: " << endl;
			divisor = 1;
			count2 = 1;
			while (divisor <= num)
			{
				if (num % divisor == 0)
				{
					cout << divisor << "\t";
					if (count2 % 5 == 0)
					{
						cout << endl;
						count2 = 1;
					}
					else count2++;
				}
				divisor++;
			}
			count -= 16;
			cout << "\n";

		}