Nested Loops homework problem.

[hjcoding]

Can anyone help me with this nested loops homework problem? I'm stuck on it and I'll be beyond grateful for anyone's help.

2. Request an integer value n.
Output a n x n grid from 1 to n inclusive where the following is true:
For each factor f of n:
If the current row number is equivalent to f, output f X’s.
Otherwise output blank spaces or lines (for non-factor rows).

Example Output (input in bold italics)
Enter an integer: 6
X
X X
X X X
(blank)
(blank)
X X X X X X

[salem c]

So what are you stuck on?

- reading an integer?

- determining if one number is a factor of another?

- printing some given number of X on a line.

In other words, code what you know then ask about where you're actually stuck.

[Grime]

Let me re-frame the question.

-> Request an integer value n.
-> Loop through 1 to n (let the counter variable be named 'i').
-> If the counter variable 'i' divides n evenly, print 'i' number of Xs.
-> Print a new line after every iteration.

So you're gonna require a for-loop to iterate 1 through n and another for-loop inside this for-loop to print Xs.

[MikeStgt]

One for() loop only:

// Example program
#include <iostream>
#include <string>
using namespace std;

int main()
{
    unsigned n;
    string str;
    
    cout << "Enter a positive integer pls: ";
    cin >> n;
    
    for (uint i=1; i <= n; ++i)
    {
        str = '\0';
        if (n % i == 0)
            cout << str.append(i, 'X');
        cout << "\n";
    }
    cout << "Done";
}