Display Days in a Month including leap year

[frenijanks]

I'm new to programming and am taking a class in school. Our assignment is to display the day in a month taking into account leap years. This is what I have so far and I keep getting an error for the bolded line.

#include <iostream>
using namespace std;
int main ()

{
	int month, year, days;
	bool is_leap_year;
	cout << "Please enter the four digit year: \n";
	cin >> year;
	cout << "Please enter the two digit month: \n";
	cin >> month;
	if ((month == 4) || (month == 6) || (month == 9) || (month == 11))
		days = 30;
	else if	(month == 2)
	{	
		is_leap_year = ((year%400) == 0) || (year% 4 == 0) && ((year%100) !== 0);
		days = is_leap_year?
		29:28;
	}	
	else 
		days = 31;
		
	return 0;
}	

Any help would be great. Thanks

[TheIdeasMan]

remove the semicolon after the if condition on line 13.


Also this all on one line:
days = is_leap_year ? 29 : 28;

[pogrady]

checking for a condition like you are doing on line 16 normally doesn't usually return a result.

try this:

if(((year%400) == 0) || (year% 4 == 0) && ((year%100) !== 0))
   is_leap_year = true;

also

the use of the ternary operator is not correct. it should be :

(is_leap_year)?days = 29:days = 28;

[cire]

the use of the ternary operator is not correct.

His usage was entirely correct, although a little awkward with the line break.