making change in dollars project question

[supersixone]

Hello I'm working on this problem where the user inputs an amount of money between $0.00 and $19.99, and the program outputs the best way to calculate the change of that amount. So for example, if I put in "$9.94", then the program should output

One $5 bill
4 $1 bills
3 quarters
1 dime
1 nickel
4 pennies

I started doing this:

float x;
cout << "Input a dollar amount between 0.00 and 19.99 inclusive: ";
cin >> x;

cout << "Change of " << x << " is best given as: " << endl;

if (x > 10.00)
{
  cout << "One $10 bill" << endl;
}

else if (5.00 < x && x <= 9.99)
{
  cout << "Two $5 bills" << endl;
}

else if (0.00 < x && <= 5.00)
{
  cout << "Three $5 bills" << endl;
}

but I feel like its really inefficient and am wondering if you guys can point me in the right direction as to how to make this program. I can't think of a way to use loops in this, but if there is a way, will you let me know?

Thanks for reading

[Disch]

Yes that is very inefficient.. and it will require much more coding than a simpler alternative.

1) Use variables. Make a variable that counts how many of each bill/coin you need.

2) Use division (/) and mod (%) operators to easily find out how many coins you need. Note that mod only works with integers, so I could multiply by 100 to get rid of that floating point.

hint:

This should require exactly zero if statements. You should be able to do it all with math.

[TheJJJunk]

See
http://www.cplusplus.com/forum/general/80061/

[supersixone]

ok thanks

how would you implement the multiplying 100 part? Like for example, if I wanted to find the number of 10 dollar bills it had to use,

tenDollar = total*100 % 10*100

like that?

[EddieV223]

I suggest writing a class that stores Money in ints.

class Money
{
int mDollars;
unsigned int mCents;

// then fill in the required methods for manipulating this data.
};