FML I don't know shit about logic

[Momojams]

So this assignment's due in about an hour and 15 minutes...
And I'm just out of my mind with frustration.
So out of desperation I'm pleading for help

Here's the prompt:

Design a C++ program to convert fractions into one of the following standard formats (whichever is appropriate):

* numerator/denominator (4/7)
* whole_number numerator/denominator (3 10/12)
* whole_number (-83)
.

#include <iostream>
#include <iomanip>

using namespace std;

int main ()
{
  double num, denom;
  int whole;
  char ch1;
  cout << " Please enter a fraction (numerator / denominator) " << endl;
  cin >>  num >> ch1 >> denom;
  if ( num == denom && denom == num)
    {
      whole = num/denom;
      cout << whole << endl;
    }
  if ( num >= 0 && denom >= 0)
    {
      whole = num/denom;
      cout << whole << endl;
    }
  if ( num <= 0 && denom <= 0)
    {
      whole = num/denom;
      cout << whole << endl;
    }
  if (num <= 0 && denom >= 0)
    {
      whole = num/denom;
      cout << whole << endl;
    }
  if (num <=0 && denom >= 0)
    {
      static_cast<int>(whole = num/denom);
      cout << whole << endl;
    }



  return 0;
}

My if statements don't account for a lot of things...

[TheIdeasMan]

double num, denom;

Do these have to be double? Ints would be a lot easier. You shouldn't make direct comparisons between doubles, because of the binary fraction representation - not all real numbers can be stored exactly, so direct comparisons quite often fail.

To do this assignment, you also need a Greatest Common Denominator function, so you can rationalise fractions such as 4 / 6 into 2 /3.

HTH Good Luck

[Moeljbcp]

#include <iostream>

using namespace std;

int main ()
{
  int num, denom;
  char ch1;
  cout << " Please enter a fraction (numerator / denominator) " << endl;
  cin >>  num >> ch1 >> denom;

  cout << "Converted number: ";

  if (num % denom == 0)
  {
	  cout << num/denom << endl;
  }
  else if (num < denom)
  {
	  cout << num << "/" << denom << endl;
  }
  else if (num > denom)
  {
	  cout << num/denom << " " << num%denom << "/" << denom << endl; //Dividing an int by an int will just truncate: 5/2 = 2.  8/3 = 2 and so on.
  }

  return 0;
}

I would recommend something like this. Please look up the MODULUS operation (%), as it's very useful for this. It returns the remainder after division. Good luck and hopefully you can stick with your class!
E: You may also wish to modify this to check for a denominator that is ZERO before performing any division with it. Sorry. And don't worry about reducing the fractions -- the prompt gives an example output of "10/12", which is not reduced.

[Momojams]

Bro I love you.
No words...