output

[geekocoder]

Can anyone plz explain me the output of the following program

#include <stdio.h>
int main()

{

 int c=5;

 printf("%d\n%d\n%d", c, c <<= 2, c >>= 2);

 getchar();

}

[LB]

It is undefined; the order of evaluation of expressions passed as parameter is not guaranteed to be one way or the other.

[ne555]

undefined behaviour is undefined

[geekocoder]

isn't C's calling convention from right to left???if not then can anyone explain me the output of the following

int a = 1 ;
printf ( "%d %d %d", a, ++a, a++ ) ;

[LB]

The calling convention is not the same as the order of evaluation. The values of the parameters may be evaluated in any order regardless of the calling convention used.