how to compare unsigned int and int ?

[vijkrr]

hi


int main()
{
unsigned int u = 10;
int i = -1;


if ( i <= u )
{
cout<<" I is less than "<<endl;
}
else
{
cout<<" U is less than "<<endl;
}

}

the output i'm getting is U is less than. How it works?
Not able to get the internall logic in this. Can any one explain me hw?

Thanks in advance..

[TaikoDragon]

it appears that "i" is being cast to an unsigned int which would make it a very large number (the int max)
the way the computer handles negatives is that the number is INTMAX - value ..if that is converted to a unsigned the negative number is suddenly positive .. more technically the highest bit is called the sign bit..it's 1 for negative numbers and 0 for positive..when you relate that to pure counting it means the upper half of the range of an int is considered negative when it's a signed int

[firedraco]

If you want to actually compare them, you will have to cast them both up to a higher signed time like a long int.