Creating an array with random letters

[student6579]

i have created this program but getting random numbers how do i get random letters instead of numbers.


#include "stdafx.h"
#include <iostream>
#include <cmath>
#include <cstdlib>
#include <ctime>
using namespace std;

const int N = 5, M = 5;

void printArray(int x[N][M])
{
for (int r = 0; r<N; r++) {
for (int c = 0; c<M; c++)
cout << x[r][c] << " ";
cout << endl;
}
}

int main()
{
int A[N][M];
srand(time(0));

for (int r = 0; r<N; r++)
for (int c = 0; c<M; c++)
A[r][c] = rand() % 100;
printArray(A);
cout << endl;

printArray(A);

system("pause");
return 0;
}

[CS Student]

Cast your numbers to a char. For example:

char a = 65;

Stores the character representation of 65 (which is an 'A') into the variable a. There are multiple ways to cast data types. Google it. There is lot's of tutorials there.

[HOWDOIAIM]

First of all, please learn to use tags, it'll make your code easier to read
http://www.cplusplus.com/articles/z13hAqkS/

As for the code, you'll want to typecast the output as char, like this
cout<< (char) x[r][c] << " ";
You'll also want to replace the rand() % 100;
with rand() % 25+65

[student6579]

im still kind of confused. isnt there a way where i have to program generate random letters. like right im getting random numbers generated between 1 and 100.

[HOWDOIAIM]

I don't think there is really any way to generate random characters, but typecasting random numbers as chars should be enough.

[student6579]

Thank You HOWDOIAIM.

[Chervil]

    char A[N][M];
    
    for (int r = 0; r<N; r++)
        for (int c = 0; c<M; c++)
            A[r][c] = rand() % ('z' - 'a' + 1) + 'a';

The expression ('z' - 'a' + 1) evaluates to 26, which is the number of letters in the alphabet. I wrote it that way to show how to use it in other cases. Say you wanted to generate letters from 'M' to 'P', you could write rand() % ('P' - 'M' + 1) + 'M';