Hybrid password

[hewell]

Hello guys password in my code must escape the hacker.I tried to do something with swap but I couldn't make the loop.Could you help please

#include <stdio.h>

void swap(int *value,int*Hybridized_Password){
	int swap_operand =*value;
	*value =*Hybridized_Password;
	*Hybridized_Password = swap_operand;
}
int main()
{
	int a=1111
	int password[4] ={9999};
	printf("\nBefore Swapping Hybridization:a=%d & password[0]=%d\n",a,password[0]);
	
	swap(%a,&password[0]); // a and default password go swap function
	
printf("\nAfter Swapping Hybridization:a=%d &password[0]=%d\n",a, password[0]);
}

[jonnin]

did you mean swap(&a
do you understand what {9999} did?
you have an array with {9999,0,0,0} is this your intent?
are you trying to swap digits? its really unclear.

[hewell]

the letters will escape to the farthest values ​​with ascii code.
Example my password abcd.For example my password is ABCD. if the hacker approaches my password, thanks to ascii code will be missed Will be 9876