help me to converting a char (-) into an operator (+)

[viliml]

Cmon guyz, any ideas at all? I'm bored!!

[viliml]

Come ON!!!

[vlad from moscow]

@viliml

No, it shall not! I tried it out with this example:cout<<char_to_op<int>('^')(3, 2);
Do you have any examples that really DON'T work?

Here is a simple example

#include <cmath>

int main()
{
   int x = 2, y = 3;

   std:pow( x, y );
}

[viliml]

sure, that doesn't work, but when its used in my function, it works!

[vlad from moscow]

@viliml

sure, that doesn't work, but when its used in my function, it works!

It is implementation-defined behaviour and other compilers can do not compile this code. Your compiler compilers this code because it places C-standard functions in the global namespace and you use pow without nested name std::. However as I have said it is not obligatory that an implementation shall place C-standard functions in the global namespace.

[viliml]

No, it doesn't put it in then global namespace! I put using namespace std; at the top of every code. :D

[Zephilinox]

that's what puts it in the global namespace

[viliml]

Oh.

[vlad from moscow]

@viliml

No, it doesn't put it in then global namespace! I put using namespace std; at the top of every code. :D

In this case your code shall ot be compiled if you will use objects of type int because the compiler will not know which overloaded function pow to use.

[viliml]

Really? It works every time on my comp(which can be either computer or compiler)!Try this out:

cout<<char_to_op<int>('^')(1, 2)<<endl;
int x=char_to_op<int>('^')(3, 4);
if (char_to_op<int>('^')(6, 5)==7776) cout<<"See? It works!"<<endl;

It works on my comp, let's see if it's implementation-specific.

[viliml]

bump

[vlad from moscow]

When please answer which pow function shall the compiler select? It has three functions

float pow( float, float );
double pow( double, double );
long double pow( long double, long double );

I think your code works due to a bug of the compiler you are using.

[TheIdeasMan]

Anything from the OP yet?

[viliml]

Nope. Not a word...