Help with having to enter values twice.

[enosmac]

I have some code that is giving me fits. I need to check that the data entered by the user is an integer between 0 and 10. This code is broken because the user has to enter their number twice (hitting enter after each input). It does work that it catches non-integers or numbers less than 0 or greater than 10, but you still have to enter the number twice. How can I fix this code so I only have to enter the number once? This is in a switch statement, which might be why??

case 2:	{
char blank;
int value;
cout << "Using overloaded constructor" << endl << endl;
cout << "Choose a integer 0-10 for Matrix Row and Column Size." << endl;
cin >> value;

//if I remove the while below, it works fine. I have tried removing
//the cin.clear and cin.ignore to no effect

while ( !(cin >> value) || value < 0 || value > 10){

cout << " PLEASE SELECT YOUR MATRIX SIZE, 0-10: ";
cin.clear();
cin.ignore (1000, '\n');
}
Matrix neo(value);
cout << "Matrix Created with overloaded constructor." << endl;
cout << "Displaying Matrix using overloaded << operator." << endl;
cout << neo;
cout << endl << endl;
cout << "Press ENTER to continue." << endl;
cin.get(blank);
cin.get(blank);

}
break;

Can anyone suggest a better way to check for integer values being inputted rather than the while statement?
Thanks a TON.

[whitenite1]

@enosmac

You could try something along these lines..

case 2:	{
char blank;
int value=-1;
cout << "Using overloaded constructor" << endl << endl;
do
{
cout << "Choose a integer 0-10 for Matrix Row and Column Size." << endl;
cin >> value;
if ( value < 0 || value > 10)
  cout << " PLEASE SELECT YOUR MATRIX SIZE, 0-10, " << endl;
} while ( value < 0 || value > 10);

[enosmac]

I found out the issue. I was doing

cin >> value

twice. Once on line 6, and again on 12. I was under the assumption that the one on line 12 was just a test, not actually taking input.

Thanks all.