### Parameters

Some important parameters for functions are poin
`void somethingHappens (int *a); //pointers `

`void somethingHappens (int& a); //address `

`void somethingHappens (int arg[]); //array `
If I was to use the functions above, how would it look like? Give me examples.

Am I missing any other important ones?
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Anyone else able to help me with this?
Anyone able to figure this out or know this?
The first and third function is the same, and takes a pointer as argument. You can pass an array to the function because arrays can be implicitly converted to a pointer to the first element.

If you have a pointer to an int that you want to pass to the function you just pass it as it is.
 ``123`` ``````int* p; // Don't forget to initialize the pointer before passing it to the function. somethingHappens(p)``````

If you have an int variable, and you want to pass a pointer to that variable to the function you can use operator&.
 ``12`` ``````int i; somethingHappens(&i);``````

Passing an array will look like this.
 ``12`` ``````int array[3] = {1, 2, 3}; somethingHappens(array);``````
What is actually passed to the function is a pointer to the first element in the array, which is 1 in the example above.

The second function takes a reference to an int as argument. If you have an int variable, and you want to pass a reference to that variable to the function you just pass it as it is.
 ``12`` ``````int i; somethingHappens(i);``````
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 ``12`` ``````int a; somethingHappens(&a); // pass pointer to a ``````

 ``12`` ``````int a; somethingHappens(a); // pass a by reference ``````

 ``12`` ``````int a[5]; somethingHappens(a); // pass a as an array ``````

Missing:
 ``1234`` ``````void somethingHappens(int a); // by value int a; somethingHappens(a); // pass a by value ``````

Clear?
@Peter87
@AbstractionAnon
Thanks for explaining everything to me. This cleared up a lot of my confusion.
i have same problem... but after visited this page.... problem almost solve..
closed account (zb0S216C)
I'd just like to point something out: if you need to change the value of a built-in type through a function, don't pass it by reference; instead, prefer to return the new value:

 ``123456789101112`` ``````int CreateNew_Value(int CurrentValue) { return(CurrentValue + ...); } int main( ) { int Value(0); // Do something... Value = CreateNew_Value(Value); }``````

Wazzak
@Royeiln
What other problems do you still have?
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