ternaru operator, ostream

How does the C++ compiler evaluate
 int i=-1;

?Thanks in advance!
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Just out of interest - before we answer - what do YOU think happens??
The shift operator has highest priority compared to the conditional operator. So the expression can be rewritten the following way

( cout<<(i<0) ) ? getch() : getch();

So the first getch will be executed because the value of the expression ( cout<<(i<0) ) which ihas type of std::ostream will be converted to const void * which will not be equal to zero if there was no any error.
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getch() will only be rewritten once.

This comiles in visual studio 2010

#include <iostream>

int main()
	int i = 0;
	std::cout << (true? ++i : ++i) << std::endl;
	std::cout << i                 << std::endl;
my problem is with the ostream obkect.Why is it non-zero?

I don't see and overloading for operator== in
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there are at least 3 consecutive things happening with this expression.( cout<<(i<0) )

1. The first thing is the (i<0) test. The result will be a bool value of either true or false.

2. The next thing that happens is the cout << - this outputs the value of the first test obviously.
if you send a boolean value to a stream you will get 1 if the value is true or 0 if it is false - so you should see either a 1 or a 0 on the console screen.

3. The << function overload returns a reference to itself.
The last test is if this cout is true or false.

But how can a ostream (or istream) object be tested for truthness.
The ostream class keeps an internal record of it's current state - if you ask a stream to ouput or input some value and that operation fails then
the stream will set it's internal state to BAD - if it succeeded it will set it's state
to GOOD.

The stream class also have a boolean operator overload function.
boolean overlaod functions allows a class to be used in an expression where
true or false is required such as an if statement:

if ( some_expression_to_be_tested_for_truth) //

If you put an ostream or istream object in such a position - it
will give a result of true if it's internal state is GOOD , or false if it is in a bad/failed state.

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It is interesting to note that before the C++ 2011 there is no conversion operator to bool in stream classes. There is conversion operator to void * in the C++ Standard before 2011.
Now instead of operator operator void* the C++ Standard defines operator explicit operator bool.
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