LSH without carry

[huvcbo]

Hi,
need help with this
K1 = (S << 1) XOR R64, where S << 1 means the data string S shifted one bit left
without carry.
unsigned char S[] = "F7BAA8735192E44A";
what is without carry?

/huvcbo

[kbw]

http://en.wikipedia.org/wiki/Bitwise_operation#Bit_shifts

[Stewbond]

Does this answer your question:

1 2 3 4 5 6 7 8 9

#include <iostream> int main ( ) { unsigned char S[] = { 0xF7, 0xBA, 0xA8, 0x73, 0x51, 0x92, 0xE4, 0x4A }; for (int i = 0; i < 8; ++i) std::cout << std::hex << (S[i] << 4) << ' '; }

f70 ba0 a80 730 510 920 e40 4a0

[huvcbo]

Yes Thanks,
but what is 'without carry' and 'with carry'
/