Can anyone convert this psuedo function code to c

[lemonysage]

Anyone have any idea how to convert this psuedo code to c++

  Function roundValue(Declare value, decimalPlaces)
	i = 0
	magnitude = 1
	FOR i = 0 To decimalPlaces
		magnitude = magnitude * 10
	END FOR
	
	value = value * magnitude
	value = (int,value + 0.5)
	value = value / magnitude
	return value
END FUNCTION

[S G H]

Did you even try?

[lemonysage]

yes, And I failed miserably, I have another thread up, I tried to convert it... Its just not clicking for me... Not sure why

[lemonysage]

http://www.cplusplus.com/doc/tutorial/functions/ Ive been through this, still doesnt make it any clearer for me. I dont expect you do it, can someone just make it clearer or point me in right direction, im so confused

[lemonysage]

float roundvalue(int value, int DecimalPlaces,);
i=0;
magnitude = 1;
for(i=0;i=DecimalPlaces;i++)
{
magnitude = magnitude *10
}
value = value*magnitude
value=(int)value+.5)
value=value/magnitude)

here was one attempt, close?

[JLBorges]

//Function roundValue(Declare value, decimalPlaces)
double round_value( double value, int decimal_places )
{
	//i = 0
	//magnitude = 1
	int magnitude = 1 ;

	//FOR i = 0 To decimalPlaces
	for( int i = 0 ; i < decimal_places ; ++i )
		magnitude = magnitude * 10 ;
	//END FOR

	value = value * magnitude ;

	//value = (int,value + 0.5)
	value = int( value + 0.5 ) ;

	value = value / magnitude ;

	return value ;

//END FUNCTION
}

[lemonysage]

Another go that doesnt work.
float roundvalue(float value, int DecimalPlaces);
int magnitude=1;
magnitude=magnitude*10;
value=value*magnitude
value=(int)value+.5)
value=value/magnitude);

[lemonysage]

//Function roundValue(Declare value, decimalPlaces)
double round_value( double value, int decimal_places )
{
	//i = 0
	//magnitude = 1
	int magnitude = 1 ;

	//FOR i = 0 To decimalPlaces
	for( int i = 0 ; i < decimal_places ; ++i )
		magnitude = magnitude * 10 ;
	//END FOR

	value = value * magnitude ;

	//value = (int,value + 0.5)
	value = int( value + 0.5 ) ;

	value = value / magnitude ;

	return value ;

//END  

Hi, would i need to declare the i as an int before this? or its not needed?

[lemonysage]

for( int i

or is that declaring it there?, didn't realise you could do that

[lemonysage]

I put this into my code.

	/*Round each number*/
	double round_value(double value, int decimal_places)
	{
		int magnitude = 1;
		for (int i=0 ;i=decimal_places;i++)
		{
			magnitude=magnitude*10;
		}
		value=value*magnitude;
		value=int ( value +.5);
		value = value/magnitude;
		return value;

	}

But im getting an error on my first {, it says it expected a ";", when i put one decimal_places);, u get a load more errors through the code.

[xismn]

double roundValue(double value, int decimalPlaces) {
	double magnitude=1.0;
	for(unsigned int i=0; i<decimalPlaces; ++i) {
		magnitude*=10;
	}
	value*=magnitude;
	value=int(value+0.5);
	value/=magnitude;
	return value;
 }

[lemonysage]

Thanks for your response, its still giving me an error on the first {

(error C2601: 'round_value': local function definitions are illegal)

[lemonysage]

Bump, anyone?

[xismn]

It seems as though you are doing something like this:

int main(int argc, char* argv[]) {

	double round_value(double value, int decimalplaces) {
	//...
	}
	return 0;
}

Which is illegal.