checking If a vector contains x integers?

[aggsyb]

If I have a vector that contains 5 integers 2,6,9,19,20 , how can I write an if statement to say if the vector 'contains' 3,6,7,10,21 then do x (the vector changes its values in each loop) so I want to write an if statement to say if it matches the exact values I wrote do something.

The "simplest" way I guess would be a long statement to say if myvec[0] == 3 && myvec[1] == 6 .... but is there a cleaner way than that?

[LB]

See the example program:
http://www.cplusplus.com/reference/algorithm/search/

[Silvestar]

store that 5 ints in array, now go 'for' loop and then compare each array

hope it helps :[]

[keskiverto]

Also: http://www.cplusplus.com/reference/algorithm/mismatch/

[Josue Molina]

Do 3, 6, 7, 10, and 21 need to be in that order?

[aggsyb]

No, but the vector is sorted so thats how they will end up

[LB]

Did you check those links kesk and I posted? Do you need help?

[JLBorges]

> The "simplest" way I guess would be a long statement to say if myvec[0] == 3 && myvec[1] == 6 ....
> but is there a cleaner way than that?

Two vectors (of the same type) can be lexicographically compared for equality with == .
http://en.cppreference.com/w/cpp/container/vector/operator_cmp

#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>

int main()
{
    std::vector<int> seq { 6, 21, 7, 3, 10 } ;

    if( seq == std::vector<int>{ 3, 6, 7, 10, 21 } ) std::cout << "equal\n" ;
    else std::cout << "not equal\n" ;

    std::sort( std::begin(seq), std::end(seq) ) ;

    if( seq == std::vector<int>{ 3, 6, 7, 10, 21 } ) std::cout << "equal\n" ;
    else std::cout << "not equal\n" ;
}

http://coliru.stacked-crooked.com/a/c6d3f0d7d2dd5f8c