Array to store value each time calculated by equation whenever the function is called

[Aisha1234]

Hello everyone! I am new to c++. I have to calculate a value via equation and store that each time whenever the function is called. I have created an array of size 10 and calculated myValue then tried to store that value. Is this program correct?

static double
CalculatemyValue(Node* ch)
{ 
	float gamma=0.3;
	double myValue = 0.0;
       int n[10];
       int i = 0;
       n[i] = myValue;
       myValue = ((1-gamma)*n[i-1]) //previous value
return myValue;
} 

[MikeyBoy]

Nowhere do you ever increase the value of i. Every time you call this function, you change the value of the first entry in the array. Also, when i is 0 (as it always is), then what will the value of i-l be? What will the value of n[i-1] be?

[Aisha1234]

Should I use a loop here? Actually I had a doubt that If I am using a loop here
n[i] = myValue;
for( int i = 1; i < 10; i++ ) {
myValue = ((1-gamma)*n[i-1])
}
then it will calculate 10 values in first call. While my task is to calculate the only 1 value in each call. In next call it should calculate 2nd myValue and store that Value. In 3rd call it should calculate 3rd myValue and so on.

[TheIdeasMan]

Hi,

You are also assigning a double value to an int array, which won't fly very well :+)

[Aisha1234]

Then how should I implement it?