If statement for additional column

[MegaKarg]

Hello
I have a problem with the following code
It is supposed to create something like a chessboard using symbols for n symbols as side of a square and n squares for side of a chessboard
My question is how to make an if statement for odd cases of n. Because I added that it will create additional row at the top, but I'm struggling how to create such column at the end or at the beginning of the square. Basically I have no idea how to create if statement that will make one column that will look like
1*n
n
0*n
n
1*n
n
0*n
n
1*n
n
I feel like this is hard to explain for me what is the problem but hopefully it is understandable

  #include "pch.h"
#include <iostream>
using namespace std;
int main()
{
	int size;
	cout << " Input the number of characters for a side: ";
	cin >> size;
	int size2 = size;
	cout << endl;
	int row2 = 1;
	if (size2 % 2 == 1) {
		for (int row = 1; row <= size; ++row)
		{
			for (int col = 1; col <= size / 2; ++col)
			{
				for (int row = 1; row <= size; ++row)
					cout << "1 ";
				for (int row = 1; row <= size; ++row)
					cout << "0 ";
			}
			cout << endl;
		}
	}
	for (row2; row2 <= size/2; ++row2)
	{
		
			for (int row = 1; row <= size; ++row)
			{
				for (int col = 1; col <= size/2; ++col)
				{
					for (int row = 1; row <= size; ++row)
					cout << "0 ";
					for (int row = 1; row <= size; ++row)
					cout << "1 ";
				}
				cout << endl;
			}

			for (int row = 1; row <= size; ++row)
			{
				for (int col = 1; col <= size/2; ++col)
				{
					for (int row = 1; row <= size; ++row)
					cout << "1 ";
					for (int row = 1; row <= size; ++row)
					cout << "0 ";
				}
				cout << endl;
			}
		
	}
		return 0;
	}

[keskiverto]

I'm not quite sure what you do ask.

Is it just the math?

#include <iostream>

int main()
{
	for ( int row=0; row < 10; ++row ) {
	    std::cout << row << '\t';

	    if ( !(row % 2) ) std::cout << ( row % 4 ? "0*" : "1*" );
	    std::cout << "n\n";
	}
}

[Manga]

#include "pch.h"
#include <iostream>
using namespace std;
int main()
{
int size;
cout << " Input the number of characters for a side: ";
cin >> size;
bool b = true;
for(int l = 0; l < size; l++) {
  for(int k = 0; k < size; k++) {
	   if(l % 2 == 0) {
	       b = true;
	   }
	   else {
	       b = false;
	   }
	for(int j = 0; j < size; j++) {
          for(int i=0; i < size; i++) {
            cout << b;   
          }//i
          b = !b;
       }//j
      cout << endl;
  }//k
}//l

		return 0;
	}

[lastchance]

#include <iostream>
using namespace std;

int main()
{
   const char SYM[2] = { '1', '0' };
   int N;
   cout << "Input N: ";   cin >> N;   cout << '\n';

   for ( int I = 0; I < N; I++ )
   {
      for ( int i = 0; i < N; i++ )
      {
         for ( int J = 0; J < N; J++ )
         {
            char c = SYM[ ( I + J ) % 2];
            for ( int j = 0; j < N; j++ ) cout << c;
         }
         cout << '\n';
      }
   }
}

Input N: 4

1111000011110000
1111000011110000
1111000011110000
1111000011110000
0000111100001111
0000111100001111
0000111100001111
0000111100001111
1111000011110000
1111000011110000
1111000011110000
1111000011110000
0000111100001111
0000111100001111
0000111100001111
0000111100001111


Input N: 5

1111100000111110000011111
1111100000111110000011111
1111100000111110000011111
1111100000111110000011111
1111100000111110000011111
0000011111000001111100000
0000011111000001111100000
0000011111000001111100000
0000011111000001111100000
0000011111000001111100000
1111100000111110000011111
1111100000111110000011111
1111100000111110000011111
1111100000111110000011111
1111100000111110000011111
0000011111000001111100000
0000011111000001111100000
0000011111000001111100000
0000011111000001111100000
0000011111000001111100000
1111100000111110000011111
1111100000111110000011111
1111100000111110000011111
1111100000111110000011111
1111100000111110000011111