How to set the value 0xEB90 into 2 Bytes?

br1039 (75)
The site http://easycalculation.com/hex-converter.php converts the value EB90 to 60304 wich is also found with:

1
2
3
 
QString strStart = "EB90";
bool ok;
unsigned int startWord = strStart.toUInt(&ok, 16);

To store EB90 in 2 Bytes, one could do:

short x = startWord;

Now debugger says that the value of x is -5232.

What is the standart/correct way to put EB90 (0xEB90 or EB90H) into 2 Bytes?

Thanks in advance.
Last edited on
Chervil (1206)
Your debugger is correct. 
1
2
3
4
5
6
7
8
9
10
11
12
 
#include <iostream>
#include <iomanip>

    using namespace std;

int main()
{
   short int a = 0xEB90;
   cout << "a = " << a << "  (dec)" << endl;
   cout << "a = " << hex << a << " (hex)" << endl;
   return 0;
}
 
a = -5232  (dec)
a = eb90 (hex)


If you use an unsigned short integer, the decimal value will be 60304, but that's merely a matter of how the value is interpreted, internally it is still stored as the same binary digits.
Last edited on
fafner (238)
hmm, maybe unsigned short?
Topic archived. No new replies allowed.

C++

Forum