help guys i really need help with this problem as i have 0 knowledge regarding c++ pls help !!!

[Aravind7]

convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.

example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO)
if the input is 23456 the output is : TWO THREE FOUR FIVE SIX
if the input is 9349 the output is : NINE THREE FOUR NINE
if the input is 245 the output is : INVALID CODE (3 DIGITS)
if the input is 2344567 the output is : INVALID CODE (7 DIGITS)

step 1 : input code
step 2 : count the number of digits in the code
step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4
step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS)
step 5 : call a function called digit_name to convert each digit into its
equivalent english name. display the result
step 6 : print the digits in reverse order
eg; if input is 13453, reverse order is 35431

[Chervil]

If this is true:

i have 0 knowledge regarding c++

then the place to start is here:
http://www.cplusplus.com/doc/

[Aravind7]

this is my assignment question and i need to submit it by this tuesday

[Chervil]

If you show the code you have written so far for this assignment, we should be able to help you overcome whatever obstacles you encounter.

[Aravind7]

#include <iostream>
using namespace std;
int main ()
{
int code;
int count=0;
int k,l,m,n,o;
int A[10];
int q,r;
int h,i,j;


cout<<"key-in the code : ";
cin>>code;

l=1;
k=code;
while (k)
{
count++;
k=k/10;
l=l*10;
m=count;

}
cout<<"total digit of code : "<<m<<endl;
cout<<"result m : "<<l<<endl;

for (i=0;i<=9;i++)
A[i]=0;
i=0;
q=code;
n=l;

while (q!=0)
{
r=q;
n=n/10;
q=r/10;
r=r%10;
A[i]=r;
i=i+1;

}
for (j=i-1;j>=0;j--)

cout<<""<<A[j];

if (m<=3)
cout<<"INVALID CODE ("<<m<<" DIGITS)"<<endl;
else if (m>6)
cout<<"INVALID CODE ("<<m<<" DIGITS)"<<endl;


return 0;
}

[Aravind7]

this is what i did so far.... but my sir said it still wrong

[keskiverto]

Please, use code tags and intuitive indentation: http://www.cplusplus.com/articles/jEywvCM9/

Where is step 5?

Steps 3 and 4 should prevent further processing and output.

I cannot fathom what your loops try to do.

[Aravind7]

honestly i really have no idea what to do now .... my due date is today at 4pm.... i'm really confused ...

[keskiverto]

1. Read a word.
2. Test if word contains character '0'.
3. Test the lenght of the word.
Only if 2 and 3 were ok: 4. Call digit_name with each character.
5. Print the word in reverse.