OOP

[Slade316]

how to create an integer array dynamically?

[EnVdaProgrammer]

Can you please be more specific?? Also intergers cant become arrays

[EnVdaProgrammer]

Also OOP is not the correct title ;)

[JLBorges]

> how to create an integer array dynamically?

See: https://cal-linux.com/tutorials//vectors.html

[sasauke]

I think this is what you're looking for:

#include <iostream>
#include <new>

int main()
{
    int size = 5;
    int *arr = new int[size]; //dynamically allocating memory for your array of ints

    // The rest of the code
    delete[] arr;
    return 0;
}

EDIT: Yup, I had forgotten to use delete[]. Added it in the code. Whenever you dynamically allocate anything, you must always deallocate it in the end when you don't need it anymore.

[shadowmouse]

Except you never use delete, once again showing why you should be using a vector, or at the very least a smart pointer.

[48T7M4Gy]

#include <iostream>
#include <new>

int main()
{
    int size = 5;
    int *arr = new int[size]; //dynamically allocating memory for your array of ints

    // The rest of the code

    delete[] arr;
    return 0;
}

[keskiverto]

For completeness, the "objects":

The "vector" object:

#include <vector>
int main()
{
    int size = 5;
    std::vector<int> arr (size); // object that manages an array of ints
    // The rest of the code
    return 0;
}

The "smart pointer" object:

#include <memory>
int main()
{
    int size = 5;
    auto arr = std::make_unique<int[]>(size); // object that manages an array of ints
    // The rest of the code
    return 0;
}

Edit: initialization syntax

[JLBorges]

int size = 5;

std::vector<int> arr {size}; // creates a sequence of size 1 [5]

std::vector<int> arr2(size); //  creates a sequence of  size 5 [ 0 0 0 0 0 ]