Missing code

[saophen]

Hey so I'm having trouble placing the missing code in order to get this program to work here it is, with the missing lines at the end.

#include <iostream>
#include <string>

using namespace std;

/**
Turns a digit into its English name.
@param digit an integer between 1 and 9
@return the name of digit ("one" ... "nine")
*/
string digit_name(int digit)
{
if (digit == 1) return "one";
if (digit == 2) return "two";
if (digit == 3) return "three";
if (digit == 4) return "four";
if (digit == 5) return "five";
if (digit == 6) return "six";
if (digit == 7) return "seven";
if (digit == 8) return "eight";
if (digit == 9) return "nine";
return "";
}

/**
Turns a number between 10 and 19 into its English name.
@param number an integer between 10 and 19
@return the name of the given number ("ten" ... "nineteen")
*/
string teen_name(int number)
{
if (number == 10) return "ten";
if (number == 11) return "eleven";
if (number == 12) return "twelve";
if (number == 13) return "thirteen";
if (number == 14) return "fourteen";
if (number == 15) return "fifteen";
if (number == 16) return "sixteen";
if (number == 17) return "seventeen";
if (number == 18) return "eighteen";
if (number == 19) return "nineteen";
return "";
}

/**
Gives the name of the tens part of a number between 20 and 99.
@param number an integer between 20 and 99
@return the name of the tens part of the number ("twenty" ... "ninety")
*/
string tens_name(int number)
{
if (number >= 90) return "ninety";
if (number >= 80) return "eighty";
if (number >= 70) return "seventy";
if (number >= 60) return "sixty";
if (number >= 50) return "fifty";
if (number >= 40) return "forty";
if (number >= 30) return "thirty";
if (number >= 20) return "twenty";
}

/**
Turns a number into its English name.
@param number a positive integer < 1,000
@return the name of the number (e.g. "two hundred seventy four")
*/
string int_name(int number)
{
int part = number; // The part that still needs to be converted
string name; // The return value

if (part >= 100)
{
}
if (part >= 20)
{


}
else if (part >= 10)
{

part = 0;
}

if (part > 0)
{
}

}
int main()
{
cout << "Please enter a positive integer: ";
int input;

return 0;
}



and here are the missing lines
//missing lines
return "";
return name;
part = part % 100;
name = name + " " + digit_name(part);
part = part % 10;
cout << int_name(input) << endl;
name = name + " " + tens_name(part);
cin >> input;
name = digit_name(part / 100) + " hundred";
name = name + " " + teen_name(part);

[keskiverto]

First of all, please use code tags when posting code. See http://www.cplusplus.com/articles/jEywvCM9/
(You can edit your post to add them.)


Lets look at a fragment of your code:

int main()
{
  cout << "Please enter a positive integer: ";
  int input;
  return 0;
}

What does it do?
Should it do something more?

[Jaybob66]

you have three functions digit_name() teen_name() and tens_name().

looks like these are supposed to take an int and return a string.

int_name() and main() both have lines missing for you to fill in.

int_name() should surely take an int and return a string like the other functions.

looks like there's something missing below, what are you going to do if part > 100? all of your choices are at the bottom of your post.

if (part >= 100)
{ 
}

for example if i entered 456 you know you need to generate the text "four hundred fifty six" you dont have many options to choose from.