i need help in algorythm

[sabagventsadze]

Hello , I have to write an algorythm which will be able to give me all possible pairs from 1 to N; for exmp. N = 3; the cout must be 1 1 ; 1 2 ; 1 3 ; 2 1 ; 2 2; 2 3; 3 1; 3 2; 3 3; But the fact is that i cant use bool . any help ? I think i have to use double FOR but i dont know how . Thanks in advance

[dhayden]

I'm not sure why you'd use bool. Just use two nested for loops.
The outer loop goes through from 1 to 3 and represents the first number in a pair.
The inner loop also goes from 1 to 3 and represents the second number in a pair.
Print the first and second numbers inside the inner loop.

[sabagventsadze]

I am not that good at english or cpp to understand those sayings but imma try to :D thanks

[sabagventsadze]

#include <iostream>
using namespace std;
main(){
int n;
cin >>n;
for(int i=1;n<=100;i++){
for(int k=1;n<=100;k--){

}
}

return 0;
}
So i wrote this I need help what do i have to cout ?

[ne555]

for(int i=1;n<=100;i++){
   for(int k=1;n<=100;k--){

there are so many things wrong with just that two lines...

let's simplify the problem
you are giving n, print a list from 1 to n
write the pseudocode

[dhayden]

I like ne555's idea of starting by printing the numbers from 1 to n. Below I have temporarily removed the inner loop and replaced it with code to print i and space. Run this program (be sure to enter the value for n and press enter). What does it print? Can you figure out how to fix it?

#include <iostream>
using namespace std;

int
main()
{
    int n;
    cin >>n;
    for(int i=1;n<=100;i++){
	cout << i << ' ';
    }

    return 0;
} 

[jonnin]

it isnt required to use 2 nested loops, but that is the simple way.
the outer loop will hold a value for all the inner loops; so outer loop is 1, the inner loop might be 1, then 2, then 3, then 4, ... etc.
then the outer loop variable becomes 2, and the inner goes 1, 2, 3, 4, ... again.
if the inner and outer are the same, you don't appear to want it.
otherwise, you do.

string those ideas together...

nested loops (and any other nested code) looks about like you would expect

for(i = 1; i <= n; i++)
{ //I prefer brackets even when not needed.
for(j = 1; j <= n; j++)
{
do something
}
} //end outer loop