Question:
Say I have a box, that contains everything (Box A). Therefore, the box must contain itself. Meaning that the box has another on of itself inside it (Box B). But then would Box B then not have to contain box A as well?
std::vector<void*>* x = new std::vector<void*>;
x->push_back(static_cast<void*>(x));
std::vector<void*>* y = static_cast<std::vector<void*>*> x[0];
assert(x == y);
x contains itself.
And your box A will contain itself. Not B, Not A^1, but A.
That you have a box that contains everything. If you have two instances of this type of box, box A and box B then box A must contain box B AND box B must contain box A?
That you have a box that contains everything. If you have two instances of this type of box, box A and box B then box A must contain box B AND box B must contain box A?
No I am saying that the box will have itself inside of it, and within in that box inside of it, there will be the parent box.
No I am saying that the box will have itself inside of it, and within in that box inside of it, there will be the parent box.
In that case what constitutes inside the box? If the inside of the box is everything that is not outside the box and everything is inside the box then the box is inside itself with out any trouble.
Technically Klein bottle does contains everything in the world including itself (or doesn't conatain anything and can hold nothing it you look at it from another angle)
We don't. We have look-a-likes made from glass and stuff, but they're not actual Klein bottles. For the same reason we don't actually have Gabriels Horns.
They're technically projections onto R^3. They can be exactly visualized as the movement of two rings: http://i43.tinypic.com/2vudjxf.png
Hope it's not too confusing. The red bits are the trails the rings would leave as they move.